Question

A body of mass 3 kg hits a wall at an angle of 60∘ & returns at the same angle. The impact time was 0.2 s. Calculate the force exerted on the wall :

Answer 1

Explanation:

Given,

Normal initial velocity, v

i

=−10sin60

o

Normal final velocity,v

f

=10sin60

o

Change in momentum, $$\Delta P=m({{v}_{f}}-{{v}_{i}})=3\left[ 10\sin {{60}^{o}}-\left( -10\sin {{60}^{o}} \right) \right]=51.96\,N{{s}^{-1}}$$

Force, F=

Δt

ΔP

=

0.2

51.96

=150

3

N

Hence, force is 150√n