A body of mass 3 Kg is dropped from the height of 1 meter. The kinetic energy of the body will be ___when it touches the ground.
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Heya user !!!
Here's the answer you are looking for
A body of mass 3 Kg is dropped from the height of 1m.
So, potential energy of the body
= mgh
= (3 × 10 × 1) J
= 30J
When the body touches the ground, it's potential energy becomes zero and because of the conservation of energy, the potential energy gets converted into kinetic energy.
So, the kinetic energy of the object at the ground = potential energy of the body at 1m = 30J
Therefore, the kinetic energy of the body will be 30 J when it touches the ground.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
A body of mass 3 Kg is dropped from the height of 1m.
So, potential energy of the body
= mgh
= (3 × 10 × 1) J
= 30J
When the body touches the ground, it's potential energy becomes zero and because of the conservation of energy, the potential energy gets converted into kinetic energy.
So, the kinetic energy of the object at the ground = potential energy of the body at 1m = 30J
Therefore, the kinetic energy of the body will be 30 J when it touches the ground.
★★ HOPE THAT HELPS ☺️ ★★
Answered by
1
A body of mass 3 Kg is dropped from the height of 1m. When the body touches the ground, it's potential energy becomes zero and because of the conservation of energy, the potential energy gets converted into kinetic energy. Therefore, the kinetic energy of the body will be 30 J when it touches the ground.
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