Question

a body of mass 3 kg is thrown vertically upwards with the initial velocity of 10 m/s. calculate the maximum height reach by object .calculate time taken to come back on surface of earth

Answer 1

Answer :

Mass of body = 3kg

Initial velocity = 10m/s

We have to find, Maximum height reached by object and time taken by body to come back on the surface of earth$.$

For a body thrown vertically up with initial velocity u,

◈ Max. height reached, h = u²/2g

◈ Total time of flight, T = 2u/g

➳ H = u²/2g

➳ H = (10)²/(2×10)

➳ H = 100/20

➳ H = 5m ..... (Answer : 1)

⇒ T = 2u/g

⇒ T = (2×10)/10

⇒ T = 20/10

⇒ T = 2s ..... (Answer : 2)

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Answer 2

Answer:

Given :-

• mass of body = 3kg
• intial velocity ( u ) = 10 m/sec
• final velocity ( v ) = 0 at maximum height

To Find

• maximum height = ?
• total time = ?

Solution

1) using equation of motion

V2 = U2 - 2as

0 = ( 10 )^2 + 2*( - 10 ) *h

100 = 2*10*h

h = 5 m

2) using equation of motion

V = U + at

0 = 10 - 10*t

t = 1 sec for going maximum height

Total time = 1 + 1 = 2

Explanation:

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