A body of mass 3 kg moving at a speed is brought to rest in 0. 5 s by applying a force of 20 N.
What was the speed of the body
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initial speed = 10/3 m/s
Please refer to the image attached.
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Answer:
net force-300-20=280N (3 kg to Newton is 300N)
acceleration=net force÷acceleration due to gravity(9.81
m/s2)
ie, 280÷9.81=28.54m/s
velocity= acceleration×time
V= 14.27m/s
That being said, my answer could be wrong since in did it in rough.
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