Question

A body of mass 3 kg moving with a speed of 4 m/s collides head on with a stationary body of mass 2 kg .Their relative velocity of seperqation

Answer 1

The relative velocity  is 4 m/s.

Explanation:

Given that,

Mass of body = 3 kg

Speed = 4 m/s

Mass of stationary body = 2 kg

We need to calculate the  velocity of second mass

Using formula of velocity

$v_{2}'=\dfrac{2m_{1}}{m_{1}+m_{2}}v_{1}-\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}}v_{2}$

Put the value into the formula

$v_{2}'=\dfrac{2\times3}{2+3}\times4-0$

$v_{2}'=4.8\ m/s$

We need to calculate the velocity of second mass

Using formula of velocity

$v_{1}'=\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}}\times v_{1}+\dfrac{2m_{2}}{m_{1}+m_{2}}\times v_{2}$

Put the value into the formula

$v_{1}'=\dfrac{3-2}{3+2}\times4+0$

$v_{1}'=0.8\ m/s$

We need to calculate the relative velocity

$v_{2}'-v_{1}'=4.8-0.8$

$v_{2}'-v_{1}'=4\ m/s$

Hence, The relative velocity  is 4 m/s.

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Topic : collision

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