Question

A body of mass 300 gm is at rest. What force
in Newton will you have to apply to move it
through 200 cm in 10 sec.?
A) Zero
B) 12 Newton
C) 1.2 Newton
D) 0.12 Newton​

Answer 1

Answer:

0.012 N

Explanation:

Using equations of motion:

• S = ut + (1/2)at²

As the body was initially at rest, u = initial velocity = 0

= > 200 cm = (0)t + (1/2)a(10)²

= > 2 m = 0 + (1/2)a(100)

= > 2 = a(100/2)

= > (2*2/100) = a

= > 4/100 = a

= > 0.04 = a

Therefore,

= > Force = mass * acceleration

= > force = 300 gm * 0.04

= > force = 0.3 kg * 0.04

= > force = 0.012 N

Answer 2

Answer:

Given options are wrong.

Explanation:

Using second equation of motion,

s = ut + 1/2 at²

Given: s is 200 cm or 2 m, t is 10 sec, u is 0 m/s and mass is 300 gm or 0.3 kg.

Substitute the values,

→ 2 = (0)(10) + 1/2 × a × (10)²

→ 2 = 0 + 100/2 × a

→ 2 = 50a

→ 0.04 = a

Hence, the acceleration is 0.04 m/s².

Now,

Force = Mass × Acceleration

Substitute the values,

→ Force = 0.3 × 0.04

→ Force = 0.012 N

Hence, the force of 0.012 N is applied.