Physics, asked by kamaksha8524, 1 year ago

A body of mass 300 kg is lifted up by 2 m in 3 sec.Find quantity of power applied (g= 9.8 m/s)

Answers

Answered by saumytiwarI

1

Power = workdone/time workdone= force×displacement force=m×g Power= (m×g×displacement)/time Power= (300×9.8×2)/3 Power= 1960 Nm/sec

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