a body of mass 300g is at rest what force in newton will you have to apply to move it through 200cm in 10 sec
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Answered by
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t= 10 seconds
S distance= 200 cm=2 metres
mass = 300 grams= 0.3 kilograms.
Velocity=S/t=2/10=0.2 metre/ sec.
initial velocity u= 0
Acceleration = (v-u)/t
⇒a=(0.2-0)/10
⇒a=0.02 metre/sec²
Now mass = 0.3 kg
So force=m×a
⇒F=0.3×0.02
⇒Force=0.006 Newtons.
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S distance= 200 cm=2 metres
mass = 300 grams= 0.3 kilograms.
Velocity=S/t=2/10=0.2 metre/ sec.
initial velocity u= 0
Acceleration = (v-u)/t
⇒a=(0.2-0)/10
⇒a=0.02 metre/sec²
Now mass = 0.3 kg
So force=m×a
⇒F=0.3×0.02
⇒Force=0.006 Newtons.
plz mark as best if liked it.
Answered by
2
So 0.006 N force will be applied. As per explained in the attachment
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