Question

a body of mass 300g kept at rest breaks into two parts due to internal forces , one part of mass 200g is found to move at a speed of 12 m/s towards the east. what will be the velocity of other

Answer 1

Answer:

ANSWER

Mass of one part m

1

=200 gm

Its velocity v

1

=12 m/s towards east

So, mass of other part m

2

=300−200=100 gm

Let its velocity be v

2

.

Applying conservation of linear momentum : P

f

−P

i

Or m

1

v

1

+m

2

v

2

=0

Or 200×12+100×v

1

=0

⟹ v

2

=−24 m/s

So, the second part will fly off towards west with a velocity of 24 m/s.