Question

A body of mass 300g kept at rest breaks into two parts due to internal forces. One part of mass 200g in found to move at a speed of 12 m per second towards the east. what will be the velocity of the other part.

Answer 1

by applying law of conservation of momentum,

$mv = m_{1} v_{1} + m_{2} v_{2} \\ \frac{300}{1000} \times 0 = \frac{200}{1000} \times 12 + \frac{100}{1000}x \\ 0 = 2400 + 100x \\ x = - 24m {s}^{ - 1}$

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