A body of mass 35 kg is placed on a horizontal surface whose coefficient of friction 0.25.find the frictional force acting on it
Answers
Answered by
3
Answer:
Explanation:
Minimum force required = Limiting friction
= μN
= μmg
= 0.25 * 35 * 10
= 87.5 N
Answered by
11
Answer:
heya mate
here's ur answer
minimum force required.=limiting friction.
=μN
=μmg
=0.25×35×10
=87.5N
hope it helps u and mark it as brainliest
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