Physics, asked by 2006lijopaul, 1 year ago

A body of mass 35 kg is placed on a horizontal surface whose coefficient of friction 0.25.find the frictional force acting on it

Answers

Answered by Anonymous
3

Answer:

Explanation:

Minimum force required = Limiting friction

= μN

= μmg

= 0.25 * 35 * 10

= 87.5 N

Answered by ItsDynamoGirl
11

Answer:

heya mate

here's ur answer

minimum force required.=limiting friction.

=μN

=μmg

=0.25×35×10

=87.5N

hope it helps u and mark it as brainliest

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