Question

A body of mass 35kg is placed on a horizontal surface, the coefficient of friction
between the surfaces is 0.25. Find the applied force if the net force is 10N.
(A) 200N
(B) 150N
(C) 185N
(D) 250N
​

Answer 1

Answer:

Here net force means total force equals to 10N or this means resultant is 10N

Explanation:

first, let's find the friction

$fr = \mu \times r \\ = 0.25 \times 350 \\ = 87.5newton$

resultant 10N is a positive answer.

here friction act backwards, therefore, the resultant 10N to be positive the force we finding must be greater than our friction

F - 87.5 =10

F = 97.5N(i got this answer when the net force is 10N)

but I think net force should be 100N