Physics, asked by abhi15693, 1 year ago

a body of mass 36 g falling from a height of 2.5 m find the momentum if the velocity is doubled?

Answers

Answered by RV10

m=36g
h=2.5m
acc. to conservation of energy
P.E.+K.E. = constant
at h=2.5m
k.e. =0
P.E. = mgh=36×9.8×2.5=882m
from rel.~momentum×momentum/2mass=k.e
mom.=252kgm/s

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