A body of mass 4 kg fall freely from a height of 50 m .(a)find its initial potential energy.(b)the kinetic and potential energy after 2 sec.
0
Answers
Answered by
36
a. P.E =mgh
=4x10x50
=2000J
b.after 2 sec
H=t^2 g/ 2
=4x10/2
=20m
now
PE = mg(h-H)
= 4x10x30
=1200J
v=√2gH
=√2x10x20
=√400
=20m/s
kE=1/2 mv^2
=1/2 4x 400
=800J
=4x10x50
=2000J
b.after 2 sec
H=t^2 g/ 2
=4x10/2
=20m
now
PE = mg(h-H)
= 4x10x30
=1200J
v=√2gH
=√2x10x20
=√400
=20m/s
kE=1/2 mv^2
=1/2 4x 400
=800J
Answered by
7
hope u get your answer .
Mark me as BRAINLIEST
Attachments:
Similar questions
Chemistry,
7 months ago
Business Studies,
7 months ago
Social Sciences,
7 months ago
Computer Science,
1 year ago
English,
1 year ago