Question

A body of mass 4 kg initially at rest is subjected to a force of i6 n. What is the kinetic energy acquired by the body at the end of 10 s?

Answer 1

F = ma
6= 4×a
a=3/2

v= u + a × t
u = 0
v = 3/2 × 10
v = 15 meter per second

kinetic energy acquired = 1/2× 4 × 225 =1/2×m×(v)^2

=450J