The area of cross section of wire becomes half when its length is stretched to double. How the resistance of wire is affected in new condition?
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Hey mate !!
Here's your answer !!
We know that:
Resistance is directly proportional to area and inversely proportional to length.
Hence if we increase resistance we get increased area and decreased length and vice - versa.
Also Resistivity wont change if the length and area is changed. It remains constant for all values for a given material.
So,
Let the original length be = x
Let the original area be = y
Resistivity = k ( Constant )
So Resistance = ky / x -----( Equation 1 )
Now given that length is halved and area is doubled. Then we get,
Length = x / 2
Area = 2y
Resistivity = k ( Constant )
Now Resistance = k * 2y / x / 2
= 2 ky * 2 / x
= 4 ky / x -----( Equation 2 )
Now comparing Equation 1 and 2 we get that,
Resistance has become 4 times after modifications.
Hence Resistance will become 4 times in the new condition, if the area is doubled and length is halved.
Hope my answer helped !!
Cheers !!
Here's your answer !!
We know that:
Resistance is directly proportional to area and inversely proportional to length.
Hence if we increase resistance we get increased area and decreased length and vice - versa.
Also Resistivity wont change if the length and area is changed. It remains constant for all values for a given material.
So,
Let the original length be = x
Let the original area be = y
Resistivity = k ( Constant )
So Resistance = ky / x -----( Equation 1 )
Now given that length is halved and area is doubled. Then we get,
Length = x / 2
Area = 2y
Resistivity = k ( Constant )
Now Resistance = k * 2y / x / 2
= 2 ky * 2 / x
= 4 ky / x -----( Equation 2 )
Now comparing Equation 1 and 2 we get that,
Resistance has become 4 times after modifications.
Hence Resistance will become 4 times in the new condition, if the area is doubled and length is halved.
Hope my answer helped !!
Cheers !!
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