An elevator descends into a mined shaft at the rate of 6 m/mins of the descent starts from 10 meter above groun level Level how long will it take to rech -350 M
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Answer:
velocity = 6 m/min
total distance to be travelled = 10m + 350m
= 360m
time taken = total distance/velocity
=360/6
=60 minutes
= 3600 second
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