Question

a body of mass 4 kg is moving on the road with coefficient of kinetic friction 0.3 the force of friction acting on it is

Answer 1

Answer:

Explanation:Friction= coeff of friction mu (N)

Friction = 0.3(40)

=12N

Normal=mg =4(10)=40

Coeff of friction =0.3

Are given

Hope this helps....

Answer 2

Answer:

f = 11.76 N

Explanation:

Given that

Mass, m = 4 kg

The coefficient of kinetic friction 0.3

Let f is the force of friction acting on the body. It is given by :

$f=\mu N$

$f=\mu mg$

$f=0.3\times 4\times 9.8$

f = 11.76 N

So, the force of friction acting on it is 11.76 N. Hence, this is the required solution.