Question

A body of mass 4 kg moves under a force of 8i + 16 j + 20k, then the acceleration vector is (in m/2)

Answer 1

Answer:

2i +4j + 5k $m/s^{2}$ or 11i + 14 $m/s^{2}$  

Explanation:

by newtons second law of motion ,

F = mass x acceleration

acceleration = force/mass

                a  = (8i + 16 j + 20k) $kgms^{-2}$/ 4$kg$

                    =  4 (2i +4j + 5k) $kgms^{-2}$/ 4$kg$

                    =  (2i +4j + 5k) $m/s^{-2}$ further

                   

let us assume that variables such that j = i+1 and k + i+2

                     =  (2i +4j + 5k)  $m/s^{-2}$      

                     = 2i + 4(i+10) + 5(i+2)$m/s^{-2}$    

                     = 2i + 4i +4 +5i+ 10 $m/s^{-2}$    

                    = 11i + 14 $m/s^{-2}$