Question

A body of mass 40 kg has kinetic energy 500 J. The magnitude (numerical value) of the momentum of the body is​

Answer 1

Explanation:

k.e = 1/2 mv^2

1000/ 40 = v^2

200 = v^2

v = ROOT 200

MOMENTUM = MV

40× ROOT 200

Answer 2

Answer:

200 kgm/s

Explanation:

$KE = \frac{p^{2}}{2m}\\\\500 = \frac{p^{2}}{80}\\\\40000=p^{2}\\\\p= 200kg m s^{-1}$