Question

A body of mass 40 kg stands on a weighing machine in an accelerated lift. The reading on the scale of
the weighing machine is 300 N. Find the magnitude and direction of acceleration. (g = 9.8ms?)
1) 2.3 m/s- upward
2) 2.3 m/s2 downward
121
3) 4.6 m/s2 upward
4) 4.6 m/s2 downward​

Answer 1

Answer:

2.5m/s^2 =2.3m/s^2downwards

Explanation:

based on newton's second law net force on body equals product of its mass and acceleration we need to find the resultant force

given

gravitational force downwards =40kg=400N

normal action upward on the body from the weighting machine=weight of the body shown on the weighting machine=300N

net upward force on the body= total external upward force-total external downward force

=400N-300N

=100N

net upward acceleration =100/40=2.5m/s^2