Question

A body of mass 400g slides on a rough horizontal surface if the frictional force is 3.0 N the angle made by contact force on the body with the vertical will be

Answer 1

Explanation:

Therefore the angle made by the contact force on the body with the verticle will be 37°.

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Answer 2

The angle made by contact force on the body with the vertical will be $37^0$.

Explanation:

The mass of the body, m =400 g = 0.4 kg.

The frictional force , f = 3.0 N.

Let the contact force on the body by the surface makes an angle θ with the vertical .

Contact force is resultant of Normal reaction and friction and let normal force is N.

N = mg

N = 0.4 kg x 10 m/s^2 = 4 N.

Now,

$tan\theta=\frac{f}{N}$

substitute the given values, we get

$tan\theta=\frac{3N}{4N}$

$\theta=tan^-^1(\frac{3}{4})$

$\theta=36.87^0=37^0$

Thus, the angle made by contact force on the body with the vertical will be $37^0$.

#Learn More:  Normal force, contact force

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