Question

a body of mass 400gm slides on a rough horizontal surface.if the friction force is 3N,the angle made by constant force on the body with the vertical is (g = 10m/sce square)​

Answer 1

Answer:

Figure shows the forces acting on the body. Contact forces are Normal reaction force N and friction force μN.

Resultant of these two contact forces are shown as R. Let R makes an angle θ with vertical as shown in figure.

then tanθ = μN / (mg) = μ ............(1)

In eqn.(1) we used the condition N = mg

hence the tangent of required angle is friction coefficient.

we are given that friction force 3 N and mass of the body 400 gram.

hence μN = μ×m×g = μ×0.4×9.8 = 3 ...........(2)

we get μ = 0.765 and tan-1μ = 37º

Answer 2

Thus, the angle made by contact force on the body with the vertical will be .

#Learn More:  Normal force, contact force

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