Physics, asked by trishnakumar31191, 1 year ago

A body of mass 40kg jumps with a velocity of 5 metre per second on a stationary cart with a friction less wheel. The mass of the cart is 3kg . What is his velocity as the cart starts moving

Answers

Answered by simarnarula8
3

Answer:

the velocity will be 0ms-1

Explanation:

Answered by nikh98
1

Explanation:

for the frictionless surface,

the momentum conservation law

m1v1=m2v2

m1 men = 40 kg

v 1men = 5m/s

m2 cart = 3kg

v2 car = ?

m1v1=m2v2

v2 = 40x5/3

v2 = 66.6

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