A body of mass 40kg jumps with a velocity of 5 metre per second on a stationary cart with a friction less wheel. The mass of the cart is 3kg . What is his velocity as the cart starts moving
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Answered by
3
Answer:
the velocity will be 0ms-1
Explanation:
Answered by
1
Explanation:
for the frictionless surface,
the momentum conservation law
m1v1=m2v2
m1 men = 40 kg
v 1men = 5m/s
m2 cart = 3kg
v2 car = ?
m1v1=m2v2
v2 = 40x5/3
v2 = 66.6
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