Physics, asked by rbrohan7083, 1 year ago

a body of mass 4kg moving with uniform velocity of 5m/s .it is reacted upon a force of 12 newton.what will be it's velocity after 1second

Answers

Answered by JunaidMirza
6
F = ma
F = m(v - u) / t
12 N = 4 kg × (v - 5 m/s) / 1 s
v = 8 m/s

It’s velocity after 1 second is 8 m/s
Answered by SparklingThunder
2

\huge\purple{ \underline{ \boxed{\mathbb{\red{QUESTION : }}}}}

A body of mass 4 kg is moving with uniform velocity of 5m/s . It is reacted upon by a force of 12 N .What will be it's velocity after 1 second ?

\huge\purple{ \underline{ \boxed{\mathbb{\red{ANSWER : }}}}}

Final velocity of body = 8 m/s

\huge\purple{ \underline{ \boxed{\mathbb{\red{EXPLANATION : }}}}}

 \green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}

Mass of body ( m ) = 4 kg

Force ( F ) = 12 N

Time taken ( t ) = 1 s

Initial velocity ( u ) = 5 m/s

\green{ \large \underline{ \mathbb{\underline{TO  \: FIND : }}}}

Final velocity of body .

\green{ \large \underline{ \mathbb{\underline{FORMULAS \: USED : }}}}

 \purple{ \boxed{ \bf a = \frac{v - u}{t}   }}

 \purple{ \boxed{ \bf F = ma}}

 \green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}

\displaystyle \sf \longrightarrow  F = ma \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:   \\  \\ \displaystyle \sf \longrightarrow  F = m \bigg( \frac{v - u}{t}  \bigg)  \:  \:  \:  \:  \: \:   \\  \\ \displaystyle \sf \longrightarrow  F =  \frac{m(v - u)}{t}   \:  \:  \:  \:  \:  \:   \: \: \\  \\ \displaystyle \sf \longrightarrow  F =  \frac{mv - mu}{t}   \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \displaystyle \sf \longrightarrow  12 =  \frac{4(v) - 4(5)}{1}   \:  \\  \\ \displaystyle \sf \longrightarrow  12 = 4v - 20 \:  \:  \:  \:  \:  \:  \:   \:  \: \\  \\  \displaystyle \sf \longrightarrow  4v - 20 = 12 \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \displaystyle \sf \longrightarrow  4v = 12+ 20  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\ \displaystyle \sf \longrightarrow  4v = 32 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \\  \\ \displaystyle \sf \longrightarrow  v =  \frac{32}{4}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \ \displaystyle \sf \longrightarrow   v = 8  \: m {s}^{ - 1}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\purple{\boxed{\begin{array}{l} \sf{Final \:  velocity \:  of \:  body = 8 \: m {s}^{ - 1}} \end{array}}}

\green{ \large \underline{ \mathbb{\underline{KNOW\:MORE: }}}}

  • Acceleration

Acceleration is the rate at which velocity changes with time .

  • Initial Velocity

Initial velocity is the velocity of the object before the effect of acceleration .

  • Final Velocity

Final velocity is the velocity of the object after the effect of acceleration .

  • Force

Force is the push or pull on an object with mass that causes it to change its velocity.

   \Large{\purple{\boxed{\begin{array}{l} \textsf{Equations of motion : } \\  \\  \textsf{v = u + at} \\  \\   \displaystyle\textsf{s = ut +  $ \sf\frac{1}{2}a {t}^{2} $ } \\  \\ \sf  {v}^{2} -  {u}^{2}  =  2as \end{array}}}}

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