Question

a body of mass 5 kg changes it's velocity from 2 to5 in 4 seconds . calculate the rate of change to work done and force acting on the object​

Answer 1

Explanation:

ANSWER

Here, m=5 kg, u=5 ms

−1

, v=10 ms

−1

, t= 10s

Using v=u+at a= t

v-u = 10s(10−5)ms −1

=0.5ms −2

As F=ma

∴F=(5kg)(0.5ms −2 )=2.5N

Answer 2

Question:--

A body of mass 5 kg changes it's velocity from 2 to5 in 4 seconds. Calculate the rate of change to work done and force acting on the object.

Answer:

Given,

• Mass, m = 5 kg

• U = 4 ms-¹

• V = 8 ms-¹

• F = 10N

We know that,

• A = F/M

• = 10/5

• = 2 ms-¹

• V² - U² = 2as

• 64 - 16 = 2 × 2 × 5

• 48/4 = 5

• 5 = 12

• W = F - S

• = 10 × 12

• W = 120 J.

Hence,

The rate of change to work done and force acting on the object is 120 J.