Question

A body of mass 5 kg initially at rest is moved by a force of 2 n on a smooth horizontal surface . The work done by the force in 10 s is....?

Answer 1

Answer:

A=F/m

a=2/5 m/s²

s=1/2at² ( because u is zero)

s=1/2*2/5*10²

s=2/10*100

s=20m

w=F.S

w=2*20

w=40 J

Answer 2

Answer:

force of friction

because it is smooth surface

and

also horizontal