a body of mass 5 kg initially at rest is subjected to a force of 20 n what is ke acrequired at the end of 10 s
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F =ma
20 N = 5 kg x a
a = 4 m/s²
use kinematics equation ,
S = ut + 1/2at²
=0 + 1/2(4)(10)²= 200 m
now,
change In kinetic energy = work done
= F.S = 20 × 200 = 4000 j
20 N = 5 kg x a
a = 4 m/s²
use kinematics equation ,
S = ut + 1/2at²
=0 + 1/2(4)(10)²= 200 m
now,
change In kinetic energy = work done
= F.S = 20 × 200 = 4000 j
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