A body of mass 5 kg initially at rest, is subjected to a force of 20N. What is the kinetic energy acquired by the body at the end of 10s.(Answer:4000J)
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Given, mass of the body, m = 5kg;
Initial velocity of the body, u = 0;
Force acting on the body, F = 20N;
Time for which the force acts, t = 10s
If a is the acceleration produced in the body,
a = F/m
= 20/5
= 4m/s
Let v be the velocity of the body after 10 s.
Clearly, v = u + at
= 0+(4)×(10)
= 40m/s
Kinetic energy acquired by the body,
K.E. (Kinetic Energy) = 1/2mv^2
K.E. = 1/2 * 5 * (40)^2
K.E. = 1/2 * 5 * 1600
K.E. = 1/2 * 8000
K.E. = 4000
We also know that,
The unit we use for K.E. is Joule. It is represented by J.
So, The final answer is = 4000 J
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