Two blocks of masses 10 kg and 30 kg are placed along a vertical line. If 10 kg block is raised through a height of 7 cm, then the distance
through which other mass should be moved to raise the center of mass of the system by 1 cm is
Answers
Answered by
11
Explanation:
Correct option is
B
1 cm down
Two masses m
1
and m
2
are kept in verticle line
m
1
=10kg m
2
=30kg
y
1
=7cm y
2
=?
The centre of mass raised by 1cm
centre of mass =
m
1
+m
2
m
1
y
1
+m
2
y
2
1 =
10+30
10×7+30×y
2
40=70+30y
2
y
2
=−1
So, m
2
=30kg body should be displaced 1cm downward ,so as to raise the centre of mass through 1cm
so the correct answer is (B)
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