Question

a body of mass 5 kg is acted on by a force F which varies with the time t as shown in the given figure.Then the momentum gained by the body at the end of 10 seconds is ​

Answer 1

Explanation:

We know that the Newton's second law of motion is F=

Δt

Δp

or change in momentum

or the gain in momentum is Δp=FΔt=Area under the F-t graph

The net area till the end of t=10s is consists of a trapezium with parallel side as 10second and 8−4=4second

and the separation being 20N so area or momentum is

2

sum×separation

=

2

(10+4)second×20N

=140Newtonsecond

Option c is correct.