Question

a body of mass 5 kg is acted upon by a variable force the force varies with the distance covered by the body what is my speed of the body when the body is covered 25m assume that body starts from rest.

Answer 1

F =MA

10 = 5*a

a=2

V^2 - u^2 =2as

V^2 = u^2 + 2as

V^2 = 0 + 2(2*25)

In AB part of journey

V^2 = 100

V=10m/sec

Answer 2

Answer: The correct answer is 10 meter per second.

Explanation:

The expression for force is as follows:

F= ma

Here, m is the mass of the object and a is the acceleration of the object.

Put m= 5 kg and F= 10 N.

10 = (5)a

a = 2 meter per second square

The expression for the equation of motion is as follows;

$v^{2}=u^{2}+2as$

Here, v is the final velocity, u is the initial velocity and s is the distance.

Put u= 0, a=  2 meter per second square and s = 25 m.

$v^{2}=0^{2}+2(2)(25)$

$v=10 meter per second$

Therefore, the speed of the body is 10 meter per second.