a body of mass 5 kg is acted upon by two perpendicular forces of magnitude 8n and 6n find the magnitude and direction of the acceleration
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Answer:
a=2ms-2
Explanation:
body of mass m is 5 kg
R=√8²+[-16]² =√ 64+36 =10N
θis angle made by force of 8 N
θ=tan −1 (−6/8)=−36.87
the negative sign indicates theta clockwise direction respect to the force of magnitude 8N
force is m X a
a=f/m=10/5=2ms−2
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