A body of mass 5 kg is acted upon by two perpendicular forces of magnitude 8 N and 6 N. Find the magnitude and direction of the acceleration.
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Answer:
body of mass m is 5 kg
R=
(8)
2
+(−16
2
)=
64+36
=10N
θis angle made by force of 8 N
θ=tan
−1
(−6/8)=−36.87
0
the negative sign indicates theta clockwise direction respect to the force of magnitude 8N
force is m X a
a=f/m=10/5=2ms
−2
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