A body of mass 5 kg is kept on rough horizontal surface as shown in figure. The work done by frictional force in time interval t = 0 to t = 3s is (g = 10 ms–2)
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Explanation:
Normal Reaction on the body=N=mg=5×10=50N
Horizontal force acting on the bodyF
H
=25N
Frictional force acting on the body F
f
=μN=0.2×50=10N
Net force acting on the body F
net
=F
H
−F
f
=25−10=15N
By work-energy theorem,
KE acquired by the body= Work done on the body=F
net
.s=15×10=150J
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