A body of mass 5 kg is lifted vertically at a constant velocity of 12m. calculate a) the force applied b) work done in lifting the body c) what happens to the work performed?
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Answered by
43
a. acc to Newton's 2nd law of motion,
F=ma.
therefore, force= 5x 9.8 ( 9.8 is the acceleration due to gravity)
f = 49N
B. w= fxs (s is the displacement)
w= kinetic energy.
therefore, k.e. = 1/2mv²
k.e. is equal to 1/2x 5x 12x12
= 360 joule.
therefore work done is 3.6 x 10² joule.
F=ma.
therefore, force= 5x 9.8 ( 9.8 is the acceleration due to gravity)
f = 49N
B. w= fxs (s is the displacement)
w= kinetic energy.
therefore, k.e. = 1/2mv²
k.e. is equal to 1/2x 5x 12x12
= 360 joule.
therefore work done is 3.6 x 10² joule.
Answered by
23
Force, F = 49 N
Work done, W = 360 J
Explanation:
Given that,
Mass of the body, m = 5 kg
It is lifted vertically at a constant velocity of 12 m/s
(a) The force acting on the body is called gravitational force. The force applied is given by :
F = mg
(b) The work done in lifting the body is given by :
(c) The work performed is stored in the form of energy.
Learn more,
Work done
https://brainly.in/question/4775090
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