A body of mass 5 kg is suspended by the two strings making angle 60 degree and 30 degree with the horizontal g is equal to 10 metre per second square find the tension
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0
Answer:
T1 25N T2 25,√3
Explanation:
balancing force in x and y direction separately ,by taking component of
forces.
Answered by
0
Answer:
50/√3N , 50N
Explanation:
let the tensions be t1 and t2
T1 cos30 = T2cos60
T1 = T2√3
T1sin30 + T2sin60 = 50
2 T2√3 = 100 , T2 = 50/√3N , T1 = 50N
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