Question

A body of mass 5 kg is taken from a height 5 m to 10 m. Find the increase in its potential energy (g = 10 ms⁻²).​

Answer 1

Answer:

Increase in potential energy =(final potential energy) − (initial potential energy) = mg×(h2−h1)=5×10×(10−5)=250J.

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Answer 2

★ Given :

• ➻ Mass (m) = 5 kg
• ➻ Height₁ (h₁) = 5 m
• ➻ Height₂ (h₂) = 10 m
• ➻ Gravity (g) = 10 ms⁻²

★ Find :

• ➻ The increase in its potential energy.

★ Solution :

• Increase in potential energy = mg (h₂ - h₁)

➺ 5 ༝ 10 ༝ (10 - 5)

➺ 250 J

▣ Therefore,

• Hence, the increase in its potential energy 250 J.

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