a body of mass 5 kg is thrown downward with a velocity 20m/s . the kinetic energy at t= 2 sec is
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Answer:
3920.4
Explanation:
using v = u + gt
for g=9.8 m/s^2
v= 20 + 9.8 *2 = 39.6 m/s
so KE = 1/2 * 5* 39.6^2 = 3920.4
and if g is taken 10m/s^2
KE = 4000
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