Question

A body of mass 5 kg is thrown vertically upward with a speed of 10 metre per second.What is the kinetic energy when it is thrown? Find its potential energy when it reaches at the maximum height.What is the maximum height covered by the body?

Answer 1

We have provided with,
Mass(m) = 5 kg
Initial velocity (u) = 10 m/s

Kinetic energy =>
$= \frac{1}{2} m {u}^{2} \\ = \frac{1}{2} \times 5 \times {10}^{2} \\ = \frac{1}{ 2} \times 5 \times 100 \\ = 5 \times 50 \\ = 250 \: j$

♦Conservation of energy states that the kinetic energy at time of throwing changes gradually into potential energy.

That means,
Kinetic energy when body is thrown = potential energy at the maximum height.

(potential energy = kinetic energy)
(potential energy = 250 j)

So,

mgh = 250 j
5*10*h = 250
50*h = 250
h = 250/50 = 5 m.

height = 5 metres.

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