Physics, asked by dristiprankashyap5, 7 months ago

A body of mass 5 kg moving with a velocity of 100 ms-¹ is brought to rest by applying a force for 25 seconds.The magnitude of the applied force is​

Answers

Answered by SreeragSunil
4

Answer:

m= 5kg

u= 100m/s

v=0.

t=25s

F = ma

a= v-u/t = 0-100/25 = -4m/s^2

Magnitude of force = ma= 5×4 = 20N

(Magnitude is always positive value. So

-20 is not correct)

Answered by parasbhumbak3
2

Answer is in the photo attached check it out...

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