a body of mass 5 kilogram is acted upon by two perpendicular forces of 8 Newton and 6 Newton give the magnitude and direction of the acceleration of the body
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Answered by
11
Given
f1= 8 n
f2= 6 n
angle between both force is 90°
hence magnitude of resultant forces
=√(f1²+ f2²+ 2f1 *f2 cos90°)
= √(8²+6²+0)
= 10 Newton
direction of resultant force thita . = tan(-¹)(6/8)...
f1= 8 n
f2= 6 n
angle between both force is 90°
hence magnitude of resultant forces
=√(f1²+ f2²+ 2f1 *f2 cos90°)
= √(8²+6²+0)
= 10 Newton
direction of resultant force thita . = tan(-¹)(6/8)...
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Answered by
7
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Mass of the body, m = 5 kg
The given situation can be represent as shown in attachment (please see attached file)
The resultant of two forces is given as:
R = √{(8)^2 + (-6)^2}= √(64+36) = 10 N
θ is the angle made by R with the force of 8 N
Θ = tan^-1(-6/8) = -36.87°
The negative sign indicates that θ is in the clockwise direction with respect to the force of magnitude 8 N.
As per Newton’s second law of motion, the acceleration (a) of the body is given as:
F = ma
=> a= F/m = 10/5 = 2 m/s^2
I hope, this will help you
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