Question

A body of mass 50 kg is a volume 0.049 m cube the buoyant force on it is

Answer 1

Mass of body = 50kg

volume = 0.049 m^3

$density = \frac{m}{v} \\ \\ = \frac{50}{0.049} = \frac{50}{49} \times 1000 \\ \\ = 1020 \: \: \frac{kg}{ {m}^{3} }$

Since the density of body is more than density of water, it will sink.

When it sinks, it will displace equal volume of water.

So volume of water displaced = 0.049 m^3

mass of water = density × volume = 1000×0.049 = 49kg

buoyancy = weight of water displaced

=> buoyancy= mg

=> buoyancy= 49×10 = 490N

Hence, buoyant force is 490N

Answer 2

Explanation:

49 kgf is the correct ans