A body of mass 50 kg is suspended by two light , inextensible cables of lenghts 15 m and 20 m frim rigid supports placed 25 m apart on the same level . Find tension in the cables
Answers
Answered by
2
Answer:
T1 = 300N , T2 = 400N
Explanation:
weight of the body = 500N
cos∝ = 0.8 , sin∝ = 0,6
T1cos∝ = T2sin∝
T1sin∝ + T2cos∝ = 500
now
T1 = T2tan∝ = 0.75T2
0.6T1 + 0.8T2 = 500
0.6x0.75T2 + 0.8T2 = 500
T2 = 500/1.25 = 400
T1 = 300N , T2 = 400N
Similar questions