Question

A body of mass 500 g is at rest on a friction less surface. Calculate the distance travelled by it in 10 second when acted upon by a force of 10 N.

Answer 1

Answer:

The distance travelled by the body in 10 sec is 1000 m.

Explanation:

Given :-

• Mass of body (m) = 500 g
• Time taken (t) = 10 sec
• Force (F) = 10 N

To find :-

• Distance travelled by it in 10 sec.

Solution :-

At first we need to find the acceleration (a) of the body.

• Mass of body(m) = 500 g = 0.5 kg

★ Formula used :

${\boxed{\large{\sf{F=ma}}}}$

• [Put values]

$: \implies \sf \: 10 = 0.5 \times a \\ \\ : \implies \sf \: 0.5a = 10 \\ \\ : \implies \sf \: a = \dfrac{10}{0.5} \\ \\ : \implies \sf \: a = 20$

Then the acceleration of the body is 20 m/s².

★ Formula used :

${\boxed{\large{\sf{s=ut+\dfrac{1}{2}at^2}}}}$

Here,

• s = distance travelled
• u = initial velocity = 0 m/s
• a = acceleration = 20 m/s²
• t = time taken = 10 sec

[Put values]

$: \implies \sf \: s = 0 \times t + \dfrac{1}{2} \times 20 \times {10}^{2} \\ \\ : \implies \sf \: s = 0 + \dfrac{1}{2} \times 20 \times 100 \\ \\ : \implies \sf \: s = 10 \times 100 \\ \\ : \implies \sf \: s = 1000$

Therefore, distance travelled by the body in 10 sec is 1000 m.

_________________

Answer 2

Given:

• Mass= 500g
• Initial speed = u= 0m/s
• Time= t= 10s
• Force= 10N

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Need to Find:

• Distance travelled= s=?

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Solution:

We know,

Force= Mass × Acceleration

⟹ 10N = 500g× Acceleration

⟹ 10 N= 0.5 kg× Acceleration

⟹ Acceleration = 10÷ 0.5 $m/{s}^{2}$

⟹ $\boxed{\pink{Acceleration= 20m/{s}^{2}}}$

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We know,

$s = ut + \dfrac{1}{2} a {t}^{2}$

$\implies \:s = 0 \times 10 + \dfrac{1}{2} \times 20 \times {10}^{2} m$

$\implies \: s = 0 + 10 \times {10}^{2} m$

$\implies \: s = 1000m$

• $\red{\bold{\therefore Distance\:Travelled=1000m}}$