Question

A body of mass 500 g is at rest on a frictionless surface. Calculate the distance travelled by it in 10s when
acted upon by a force of 10-2 N.​

Answer 1

Answer:

1020 km

Explanation:

hope it helps

Answer 2

$\sf\huge{\underline{\underline{Solution}}}-$

Here,

• $\sf{F = 0.01 N}$
• $\sf{m = 500 g= 500/1000 kg= 0.5 kg}$

∵ $\sf\red{F = ma}$........................$\red{(1)}$

Substituting the values in Eqn. (1)

$\sf{a = F/m}$

$\sf\: \: \:= 0.01 N/0.5 kg$

$\sf \: \: \:= 0.2 m/s$²

∵ $\sf\red{S = ut + 1/2 at}$²........................$\red{(2)}$

Here,

• $\sf{u = 0}$
• $\sf{t = 10 s}$
• $\sf{a = 0.2 m/s}$²

Substituting the values in Eqn. (2)

$\sf{S = 0 × 10 + (1/2)0.2 × (10)}$²

$\sf\: \: \:{= 1 × 0.01 × 100}$

$\sf\: \: \:={\boxed{\underline {\sf\red{1 m}}}}.$

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