a body of mass 500 gram initially at rest is acted upon by a force it accelerates and moves a distance 4m 2 sec find accleration
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Answered by
2
Given:
m=500g=0.5kg
u=0m/s
d=4m
t=2s
a=?
s=ut+1/2at^2
4=0*2+1/2a2*2
4=2a
a=2m/s^2
m=500g=0.5kg
u=0m/s
d=4m
t=2s
a=?
s=ut+1/2at^2
4=0*2+1/2a2*2
4=2a
a=2m/s^2
Answered by
2
Explanation:
(meter=500Gram=0.5)
=0ms
=4m
=2
a=?
s=ut+1/2at^2
4=02+1/2a2'2
4=2a
a=2m/s^2
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