a body of mass 500 gram is at rest on a frictional less circumference calculated the distance travelled by it in 20 sec when acted by a force 10-2N
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Answer:
Answer
We have,
m=500g,t=10s,f=fN
Since,f=ma
So, a=
m
f
=
500
f
ms
2
Now, By using:
s=ut+
2
1
at
2
=0+0.5×
500
f
×100 Since u=0
=0.1fm
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