Question

a body of mass 500 gram is resting on a frictionless surface. calculate the distance travelled by it in 10 seconds when acted upon by a force of 10^-2 N.​

Answer 1

Distance traveled in 10 seconds = 1 metre

Explanation:

Given :

A body of mass 500 g is at rest on a frictionless surface.

When the body is acted upon by a force of N,

then find distance traveled by the body in 10 seconds .

Solution :

We know that,

Force = Mass × Acceleration ( F = ma )

Force (F) = N = 0.01 N

Mass (m) = 500 g = 0.5 kg

⇒ F = ma

⇒

⇒ ⇒ a = 0.02 m/s²

We also knew that,

Distance traveled (s) = ut + ¹/₂ at²   (here , s meant distance travelled)

here u = 0 m/s

t = 10 seconds.

a = 0.02 m/s²

⇒

⇒

⇒ = 1 m

Answer 2

AnswEr :

Given that body of mass 500 gram is resting on a frictionless surface.

We have to find distance travelled by it in 10 seconds when acted upon by a force of 10-² N.

From the given data : Mass of body (m) = 500 gram = 500/1000 = 0.5 kg. Initial speed (u) = 0 m/s [As it starts from rest] . Force acting (F) = 10-² N = 0.01 N.

From Newton's second law i.e. Force (F) = Mass (M) × Acceleration (a)

Substituting values,

→ 0.01 = 0.5 × a

→ a = 0.01/0.5

→ a = 0.02 m/s²

∴ Acceleration of body = 0.02 m/s²

Now from the 2nd equation of motion i.e. s = ut + ½ at²

Substituting values,

→ s = 0 × 10 + ½ × 0.02 × 10²

→ s = 0 + ½ × 0.02 × 100

→ s = 50 × 0.02

→ s = 1 m

∴ Distance travelled by body in 10s = 1 m (Ans.)