Question

A body of mass 500 gram is whirled in a horizontal circle of radius 50 cm with an angular speed 8tt rad/s.
The frequency of revolution in rpm and centripetal force acting on it are respectively,

Answer 1

Answer:

158 N , 240 rpm

Step-by-step explanation:

GIVEN:-

m = 0.5 kg, r = 0.5 m,

w = 8π rad/ sec = 8×22/7 = 25.14 rad/sec

SOLUTION:-

Fc = mrw²

= 0.5×0.5×(25.14)²

= 158 N

frequency = w/2π

= 8π/2π

= 4revolution/sec

= 4×60 rpm

= 240 rpm

hope this helps you